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At atmospheric pressure ethyl acetate and ethyl alcohol form an azeotropic mixture containing 53.9% mole of ethyl acetate and boiling at 71.8°C. <br/> <br/>a) Estimate the values of A & B in the empirical van Laar equation <br/> <br/>log10 ?1 = A/[1+ (Ax1/Bx2)2] <br/> <br/>log10 ?1 = B/[1+ (Bx2/Ax1)2] <br/> <br/>b) If A & B are constant, calculate the azeotropic composition and the corresponding total pressure for boiling at 56.3°C. <br/> <br/>Data: Vapour pressures of pure components (in mmHg): <br/> <br/> 71.8°C 56.3°C <br/>Ethyl Alcohol 587 298 <br/>Ethyl Acetate 636 360
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