The reactor feed is 10 gmolmin ethylene oxide and 30

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Ethylene glycol (HOCH2CH2OH), used as an antifreeze, is produced by reacting ethylene oxide with water. A side reaction produces an undesirable dime, DEG:

C2H4O + H2O----> HOCH2CH2OH
HOCH2CH2OH + C2H4O-----> HOCH2CH2OCH2CH2OH

The reactor feed is 10 gmol/min ethylene oxide and 30 gmol/min water. Why is water excess reactant? If the fractional conversion of ethylene oxide is 0.92 and the selectivity is 0.85, what is the reactor outlet composition and the yield?

Reference no: EM13640421

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