State procedure to prepare the analogous propoxy compound

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Why is it important to be certain that all of the phenol and base are in solution before mixing them?

Both the phenol and ehtyl alcohol contain OH groups. However, only the phenolic OH group reacts to any extent. Why?

If you wanted to adapt this procedure to prepare the analogous propoxy compound, how much propyl iodide would you have to use to carry out the reaction on the same scale?

Reference no: EM13180745

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