Reference no: EM13351152
Problem 1. Modify the state diagram branching conditions in the diagrams below as needed to ensure the sum and exclusion rules are obeyed in each case. You can add a holding conditions or change branch codes as desired.
Problem 2. A vending machine should SELL an item if 30 cents is input. The machine has a coin sensor that can detect nickels, dimes, and quarters, and reject everything else. No change is given (i.e, if two quarters are input, simply assert SELL and keep the fifty cents). Sketch a state diagram to assert SELL when adequate coinage has been inserted.
Problem 3. Create a state diagram for a machine that can control a 4-button digital combination lock mechanism, unlocking only if the sequence B0-B3-B1 is detected.
Problem 4. Sketch a circuit for the state machines below.
Problem 5. Sketch a state diagram based on the following Verilog Code
module fsm (
CLK, RST, X, Y, Z, RED, BLUE);
input CLK, RST, X, Y, Z;
output reg RED, BLUE;
localparam S1 = 2'd0;
localparam S2 = 2'd1;
localparam S3 = 2'd2;
localparam S4 = 2'd3;
reg [1:0] ps, ns;
always @ (ps, x, y, z)
begin
case (ps)
S1: begin
RED = 1'b0;
BLUE = 1'b0;
if (X == 1'b0) ns = S1;
else ns = S2;
end
S2: begin
RED = 1'b0;
BLUE = 1'b1;
if (X == 1'b0 && Y == 1'b0 && Z == 1'b0) ns = S2;
else if (X == 1'b1 || Y == 1'b1) ns = S1;
else if (Z == 1'b1 && X == 1'b0 && Y == 1'b0) ns = S3;
end
S3: begin
RED = Y;
BLUE = 1'b0;
if (Y == 1'b1 && X == 1'b0 && Z == 1'b0) ns = S4;
else if (X == 1'b0 && Y == 1'b0 && Z == 1'b0) ns = S3;
else if (X == 1'b1 || Z == 1'b1) ns = S1;
end
S4: begin
RED = 1'b1;
BLUE = X;
ns = S1;
end
default: begin
RED = 1'b0;
BLUE = 1'b0;
ns = S1;
end
endcase
end
always @ (CLK, RST)
begin
if (RST == 1'b1) ps <= S1;
else ps <= ns;
end
endmodule
Problem 6. Assign state codes to the state diagrams below, using unit-distance coding and/or matching state codes to outputs
