Null hypothesis and the alternate hypothesis

Assignment Help Basic Statistics

Reference no: EM1398121

Sample Information is below. Test the hypothesis at the .05 significance level that the treatment means are equal.

Treatment One Treatment Two Treatment Three

9 13 10

7 20 9

11 14 15

9 13 14

12 15

State the null hypothesis and the alternate hypothesis.

What is the decision rule?

Compute SST, SSE and SS total

Complete an ANOVA table.

State the decision regarding the null hypothesis.

Reference no: EM1398121

Questions Cloud

Addition of a specific gene : There are sixty one codons that each specify the addition of a specific gene there are no corresponding amino acid, however there are only about for anticodons how is that possible?

Levels of significance-anova-correlation coefficient : Suppose the following table shows the number of colds 7 different people got during the typical cold season based on the number of times they washed they washed their hands per day during the cold season.

How many heat calories would this person generate : If an individual was exercising at an exercise intensity of 1.5 liters of oxygen per minute, and had a mechanical efficiency of 20 percent, how many heat Calories would this person generate in 30 minutes?

Give olaf a plan of action for the future : Give Olaf a plan of action for the future that attacks the problem. Be specific and provide examples that relate to Wireless Telecom Company.

Null hypothesis and the alternate hypothesis : State the null hypothesis and the alternate hypothesis. State the decision regarding the null hypothesis.

Determine the best way to rephrase : Determine the best way to rephrase:paraphrase long passage you just read. Using reference, incorporate suitable APA-formatted.

Approximation to the sampling distribution : If the test contains 250 questions, what is the probability that Julie will score 75% or lower? (Use the normal approximation to the sampling distribution to solve this problem.)

Estimate the genotypic frequencies : Given the following allele frequencies estimate the genotypic frequencies and explain how you calculate the genotypic frequencies from the allele frequencies for both generations it would be.

What is the specific activity : You have measured the absorption of pNP created by acid phosphatase after 12.5 minutes of reaction to be 0.188. The reaction occurred in a 500 microliter volume into which was added 0.200mL of 0.400 mg/mL WAP.

User Account

All Pages