Mean and variance-binomial distribution

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A television station estimates that 50% of college students watch the super bowl. For a sample of 120 students selected at random, what is the mean and variance of the number of students who watch the game?

a mean=60.0 variance=30.00

b. mean=30.0 variance=30.00

c. mean=60.0 variance=5.48

d. mean=30.0 variance=5.48

Reference no: EM13102767

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