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we identified access to the global pointer, target, as a bottleneck in the GRR load-balancing scheme. Consider a modification of this scheme in which it is augmented with message combining. This scheme works as follows. All the requests to read the value of the global pointer target at processor zero are combined at intermediate processors. Thus, the total number of requests handled by processor zero is greatly reduced. This technique is essentially a software implementation of the fetch-andadd operation. This scheme is called GRR-M (GRR with message combining). An implementation of this scheme is illustrated in Figure 11.19. Each processor is at a leaf node in a complete (logical) binary tree. Note that such a logical tree can be easily mapped on to a physical topology. When a processor wants to atomically read and increment target, it sends a request up the tree toward processor zero. An internal node of the tree holds a request from one of its children for at most time d, then forwards the message to its parent. If a request comes from the node's other child within time d, the two requests are combined and sent up as a single request. If i is the total number of increment requests that have been combined, the resulting increment of target is i.
The returned value at each processor is equal to what it would have been if all the requests to target had been serialized. This is done as follows: each combined message is stored in a table at each processor until the request is granted. When the value of target is sent back to an internal node, two values are sent down to the left and right children if both requested a value of target. The two values are determined from the entries in the table corresponding to increment requests by the two children. The scheme is illustrated by Figure 11.19, in which the original value of target is x, and processors P0, P2, P4, P6 and P7 issue requests. The total requested increment is five. After the messages are combined and processed, the value of target received at these processors is x, x + 1, x + 2, x + 3 and x + 4, respectively.
a. What is the speedup of this processor for this program compared to a non-pipelined processor, making the same assumptions used in Section 14.4? b. What is the throughput of the pipelined processor?
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