How many ml of 0385 m perchloric acid would have to be

An aqueous solution contains 0.455 M dimethylamine ((CH3)2NH).

How many mL of 0.385 M perchloric acid would have to be added to 150 mL of this solution in order to prepare a buffer with a pH of 10.800.

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How many ml of 0385 m perchloric acid would have to be : an aqueous solution contains 0.455 m dimethylamine ch32nh.how many ml of 0.385 m perchloric acid would have to be added

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A 50g sample of a hydrate of cacl2 was heated and only 43 g : a 5.0g sample of a hydrate of cacl2 was heated and only 4.3 g of the anhydrous salt remained. what is the percentage of

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