Explain the concentrations of all species at equilibrium

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Reference no: EM13333524

At 35°C, K = 1.6 10-5 mol/L for the following reaction. 2 NOCl(g) 2 NO(g) + Cl2(g) Calculate the concentrations of all species at equilibrium for each of the following original mixtures.

(a) 3.2 mol of pure NOCl in a 2.0-L flask NOCL= NO= CL2=

(b) 2.6 mol of NO and 1.3 mol of Cl2 in a 1.0-L flask NOCL= NO= CL2=

(c) 1.2 mol of NOCl and 1.2 mol of NO in a 1.0-L flask NOCL= NO= CL2= '

(d)3.5 mol of NO and 1.2 mol of Cl2 in a 1.0-L flask NOCL= NO= CL2=

(e) 2.0 mol of NOCl, 2.0 mol of NO, and 1.0 mol of Cl2 in a 1.0-L flask NOCL= NO= CL2=

f)1.0 mol/L concentration of all three gasses NOCL= NO= CL2=

Reference no: EM13333524

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