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A certain reaction has activation energy of 44.77kJ/mol. Explain at what Kelvin temperature will the reaction proceed 6.50 times faster than it did at 313 K?
Calculate the concentration of NO3- ion remaining in solution.
The likely formula for the compound is Ni(N2H4)2(ClO4°2 where the hydrazine is a neutral ligand and the nickel is +2. If 10g of this compound reacted completely into its component elements, how many liters of gas would be produced at 298K and 1atm..
what is the solubility of O2 at an elevation of 12,000 ft where the atmospheric pressure is 0.657 atm? Assume the temperature is 25°C, and that the mole fraction of O2 in air is 0.209 at both 12,000 ft and at sea level.
If the activation energy for a given compound is found to be 103 kJ/mol, with a frequency factor of 4.0 × 10^13 s^-1, what is the rate constant for this reaction at 398 K
Predict the magnetic susceptibilities (para- or diamagnetic) and determine the number of unpaired electrons of each of the following complexes (consider C2O42- and H2O as strong field ligands which cause a large splitting of the d-orbitals).
Calculate the volume (in L) of ethylene glycol in a radiator that contains 2170 g ethylene glycol. (The density of ethylene glycol is 1.11 g/ml.)
Describe the color change of a positive Benedicts test and What group reacts with the Benedicts reagent
What is the final temperature, in ?C, of the gas in the bubble outside the volcano if the final volume of the bubble is 161mL and the final pressure is 0.827atm, if the amount of gas remains constant?
Gaseous ammonia reacts with oxygen gas to produce gaseous nitrogen monoxide and liquid water. If 750 grams of ammonia and 750 grams of oxygen gas were mixed
A .0678 g sample of tin sulfate was dissolved in dilute HCl and treated with 10% BaCl2 solution. The BaCl4 precipitate weighed .0737 g. Determine the formula of this sulfate of tin.
A piston has an external pressure of 11.0 bar . How much work has been done if the cylinder goes from a volume of 0.150 liters to 0.570 liters.
The empirical formula for the hydride of sulfur is H2S, and its central atom is sulfur. Based on this information, you would expect the empirical formula for the hydride of selenium
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