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Describe a scenario where you believe a binomial distribution would be appropriate. Describe a scenario where you believe a geometric distribution would be appropriate. Explain your reasoning for both scenarios. Discuss what could have gone wrong (from a probability standpoint) with this type of game-fixing. How confident should the conspirators have been that this plan would work? Does the selection of any of the numbers affect the selection chances of the other two numbers, and explain your reasoning.
Determine whether the following situations represent a right, left or two-tailed test: In 1997, 43% of Americans 18 years or older participated in some form of charity work.
If Smith checks 300 of the 7500 welds completed that shift, what is the probability that he will find fewer than 20 substandard welds?
A population is Normally distributed and has a σ =24. Samples of size 25 have a sample mean of 100. Find the 90% confidence interval for the population mean.
question a corporation owns several companies. the strategic planner for the corporation believes dollars spent on
question a study reported in the journal of the american medical association investigated the cardiac demands of heavy
A sample of 70 cut sheets yields a mean length of 12.14 feet. This sample will be used to obtain a 99% confidence interval for the mean length cut by machine.
use the one-proportion z-interval procedure to find the required confidence interval. be sure to check the conditions
Using a two-tailed test with a=.05 is there a significant difference between the two treatment conditions? c. compute r2 to measure the percentage of variance accounded for the by the treatment effect.
the westchester chamber of commerce periodically sponsors public service seminars and programs. currently promotional
breathing is cyclic and a full respiratory cycle from the beginning of inhalation to the end of exhalation takes about
The time, in hours, that a copying machine may work without breaking down is the normally distributed random variable with mean 549 and the standard deviation 68.
Assuming that these are a random sample of all publicly traded companies, construct a 95 % confidence interval for the overall noncompliance proportion.
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