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Question Evaluate e-5 using two approaches
e-x = 1 – x + x2/2 –x3/3!+-----
and
e-x = 1/ex = 1/1+x+x2/2 + x3/3! + --------------
and compare with the true value of 6.737947 x 10-3 . Use 20 terms to evaluate each series and compute true and approximate relative errors as terms are added.
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