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When solution of silver nitrate, AgNO3, and calcium Iodide, Cal2, are mixed, a yellow precipitation of silver iodide is formed. Calculate the mass of silver iodide that is formed in 50 mLof 1.00 M AgNO3 is combined with 30 mL of 1.25 mL CaI2.
Icebergs in the North Atlantic present hazards to shipping, causing the length of shipping routes to increase by about 30 percent during the iceberg season.
Devise a synthesis of hexanedial OHC(CH2)4CHO from phenol and any needed organic or inorganic reagents.
Construct a buffer to have a pH of 7.70 using HClO and NaClO (Ka = 3 x 10-8). How many grams of NaClO must be added to 1.0 L of a 0.40 M HClO solution (assume no volume change)
How long will it take to deposit 89 g of magnesium from an electrolysis cell containing MgO at a current of 12.5. A magnesium formation is the only cathode reaction mg = 24glmol.
A student mixed 5.00 mL of a nickel(2) chloride solution with 5.00 mL of .100M sodium phosphate and a precipitate formed. How many moles of sodium phospahte were present in 5.00 mL of the solution?
Explain what is the percentage purity of the zinc, presuming that all the zinc present reacted completely with HCl as well as that the impurities didn't react with HCl to produce hydrogen? IF the vapor pressure of water at 10 degrees C is 9.21 Tor..
Calculate the mass of magnesium hydroxide formed in the reaction of 2.0 L of a 5.8 M solution of sodium hydroxide with excess magnesium nitrate.
What is the pH of the buffer described in the above question? The formic acid (HCHO2) concentration is 0.75 M. the sodium formate (NaCHO2) concentration is 0.75 M
the average number of collisions suffered by a single molecule of nitrogen in a second. (b) the total collision frequency Zbb in 1 / (cm^3 s).
Do these lambda maxs indicate an increase or a decrease in the energy of the light absorbed as the number of EN ligands bound to Cu(II) increases
It takes 50% of NaOH to prepare .6 Normality of NaOH. How much of 50% of NaOH to prepare 50 Liters of solution
Benzoic acid reactis with sodium bicarbonate (NaHCO3) causing the benzoic acid to take up the sodium on one of the oxygen molecule and making HCO2OH
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