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An economist wants to estimate the mean income for teh first year work for a college graduate who has had the profound wisdom to take a statistics course. How many such incomes must be found if we want to be 95% confident that the sample mean is within $500 of the true population mean? Assume that a previous study has revealed that for such incomes, =$6250
While 290 out of 400 in Batavia preferred the same flavor. To test the hypothesis that there was no difference in preferences in the two towns, what is the alternate hypothesis?
Defects will go into product assembly and will have to be replaced later at a cost of $10 each when they are detected in finnal product testing.
1. questions based on a distribution of scores with and the standard deviation 6.38. draw a small picture to help
Test this problem at 99% confidence and provide conclusion. Would the problem have a similar conclusion if we knew the population standard deviation was $40,000? Why?
What is the probability that she will have at least 3 minutes to obtain her cup of tea?
suppose that for a set of numeric data we have the following sample statisticsx with bar on top equal 10y with bar on
It is believed that population standard deviation is 15 days. If test is conducted using a 0.05 level of significance, what conclusion must be reached?
Assuming that Richard guesses on all eight questions, find the indicated probabilities. What is the probability that he will answer all questions correctly?
The manager of a local branch of a bank believes that over the past few years the bank has begun to cater to a different clientele and that the average amount withdrawn from its ATMs is no longer $140.00.
Test Scores: mean=100 variance = 225 Years of Service: mean=5 variance = 81 Of test scores and years of service, which measure has the greater dispersion?
Perform exploratory data analysis on CreativityPre and CreativityPost. Using SPSS, calculate the mean and standard deviation of these two variables.
Sampling distributions. Given a normal distribution with μ = 50 and standard deviation σ = 9, if a sample of n = 100 is selected.
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