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Working Definition of Limit
1. We state that
if we can create an as close to L like we want for all adequately large n. Alternatively, the value of the an's approach L because n approaches infinity.
2. We define that
Determine if we can make an as large as we wish for all sufficiently large n. Once again, alternatively, the value of the an's get larger and larger withno bound as n approaches infinity.
3. We define that
Whether, we can make an as large and negative as we wish for all sufficiently large n. Once again, in other words, the value of the an's are negative and obtain larger and larger without bound because n approaches infinity.
6-year-old Rahul wasn't able to understand multiplication when it was thrust upon him in school. His mother discussed this problem with some of us. On the basis of suggestions that
the first question should be done using the website given (www.desmos.com/calculator )and another good example to explain using the graph ( https://www.desmos.com/calculator/ydimzr
How will you find the vertex of a parabola given in 2nd degree form (the axis of parabola is not parallel to coordinate axes)? Ans) Write the equation in type of standard form.
how to do multiplication
(a) Find the curve on the surface z=x 3/2 joining the points(x,y,z)=(0,0,0) and (1,1,1) has the shortest arc lenght? (b) Use a computer to produce a plot showing the surface an
Interpretations of the Derivative : Before moving on to the section where we study how to calculate derivatives by ignoring the limits we were evaluating in the earlier secti
Inverse Sine : Let's begin with inverse sine. Following is the definition of the inverse sine. y = sin -1 x ⇔ sin y = x for - ?/2 ≤ y ≤ ?/2 Hen
The vertices of a ? ABC are A(4, 6), B(1. 5) and C(7, 2). A line is drawn to intersect sides AB and AC at D and E respectively, such that AD/AB = AE/AC = 1/4 .Calculate the ar
L.H.S. =cos 12+cos 60+cos 84 =cos 12+(cos 84+cos 60) =cos 12+2.cos 72 . cos 12 =(1+2sin 18)cos 12 =(1+2.(√5 -1)/4)cos 12 =(1+.(√5 -1)/2)cos 12 =(√5 +1)/2.cos 12 R.H.S =c
solve the recurrence relation an=2an-1+n, a0=1
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