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If the restoring force is larger than friction, and the oscillation is classified as under-damped. In this case, ω is real and behaves exactly like the solution of an undamped oscillator. Hence, we have
q = [(A1 + A2) cos ω t + i (A1 - A2) sin ω t]= A0 sin (ω t + Ø) = A ( t ) sin (ω t + Ø)where we used, A1 + A2 = A sin Ø and i (A1 - A2) = A cos ØThe above solution shows that particle performs oscillations with frequency ω, or time period T = 2 π/ω, but with a time dependent A ( t ) = A0 . In absence of friction, = 0, the amplitude remains constant, i.e. equal to A0. In presence of friction, amplitude decays exponentially with time; the time t = τ = 1/ , when amplitude becomes 1/e of its initial value is called decay constant of the oscillator. That is,A( t ) = A0 e-t/τ= A0/e at t = τwhere A0 is the initial amplitude (or displacement) at t = 0.
I want to tranfer the rotatory motion of my apache RTR 160 back wheel to a motor(of dynamo). kindly guide me with the design. i''m struck up in the gear wheel mechanism.
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