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We know from Shannon's Theorem,Maximum data rate of a channel in bps (B) = Hlog2 ( 1+S/N ) _ 1Where H = bandwidth in HzS/N = signal-to-noise ratioWe also know thatDb = 10log10 S/NWhere Db= signal-to-noise ratio in decibel (which is in this case 20)So20 = 10 log10 S/N2 = log10 S/NAnd we get S/N = 100Putting this value of S/N in equation 1 we getB = 6000 log2 (1+100) = 6000 x 6.6582= 39949.2 bps or 39.949 kbpsSo the maximum achievable data rate here is 39.949 kbps
What is Results of Recipient Operation ? International Society for Heart and Lung Transplantation (ISHLT) maintains data from more than 300 centres starting from 1980. Data fo
INTRODUCTION : In the first unit of this block you read about hazards due to electricity and gases in the science laboratories. 'The second unit deals with yet another type of com
Explain the Secondary Active Transport In secondary active transport, there is no direct coupling of ATP; instead the electrochemical potential difference created by pumping io
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QUESTION 1 ‘First Impression is the last impression.' Discuss this very often heard quote referring to the theory of Solomon Asch. Support your answer with examples from your o
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