Quantum mechanics, Mechanical Engineering

A ball is dropped from a height .If it takes0.200 second to cross the last 6.00 m before hitting the ground ,find the height  from which it was dropped .

Ans) We need to find H

Using second eqn of motion:

6=0.2u-5(0.04).............................u is velocity at h=6m

u=31m/s

Conserving energy:

mgh=0.5m(31)2.......................................Datum line for P.E is at 6 m from ground. h= H-6

=>h=48.05m

=>H=54.05m.

Posted Date: 3/8/2013 6:27:54 AM | Location : United States





we consider a ball it is dipped from a height equal to square of the intiial distance by 2 multiplide with g(9.8),

i.e ans is 1.83 metres.

Posted by | Posted Date: 3/8/2013 6:28:27 AM


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