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Different types of applications and numerous programming languages have been developed to make easy the task of writing programs. The assortment of programming languages shows, different interpretations that can be given to information. However, from the perspective of their power to express computations, there is very minute difference among them. Accordingly different programming languages can be used in the study of programs. The study of programs can benefit, however, from fixing the programming language in use. This enables a unified discussion about programs. So the program can be defined as a finite sequence of instructions over some domain D. The domain D, called the domain of the variables, is assumed to be a set of elements with a distinguished element, called the initial value of the variables. Each of the elements in D is assumed to be a possible assignment of a value to the variables of the program. The sequence of instructions is assumed to consist of instructions of the following form.
1. Simulate a TM with infinite tape on both ends using a two-track TM with finite storage 2. Prove the following language is non-Turing recognizable using the diagnolization
We now add an additional degree of non-determinism and allow transitions that can be taken independent of the input-ε-transitions. Here whenever the automaton is in state 1
State & prove pumping lemma for regular set. Show that for the language L={ap |p is a prime} is not regular
Perfect shuffle permutation
And what this money. Invovle who it involves and the fact of,how we got itself identified candidate and not withstanding time date location. That shouts me media And answers who''v
Another striking aspect of LTk transition graphs is that they are generally extremely ine?cient. All we really care about is whether a path through the graph leads to an accepting
Find the Regular Grammar for the following Regular Expression: a(a+b)*(ab*+ba*)b.
One might assume that non-closure under concatenation would imply non closure under both Kleene- and positive closure, since the concatenation of a language with itself is included
proof of arden''s theoram
As de?ned the powerset construction builds a DFA with many states that can never be reached from Q′ 0 . Since they cannot be reached from Q′ 0 there is no path from Q′ 0 to a sta
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