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IRET : Return from ISR:-
When an interrupt service routine is called, before transferring control to it, the IP, CS register and flag registers are stored in the stack to mention the location from where the execution is to be continued, after the ISR is executed. Hence, in the ending of each ISR, when IRET is executed, the values of IP, CS register and flags are retrieved from the stack to continue the execution of the main program. The stack is modified consequently.
LOOP : Loop Unconditionally:-
This instruction executes the part of the program from the address or label mention in the instruction up to the loop instruction, CX number of times. Following sequence describe the execution. On every iteration, register CX is decremented automatically. In other terms, this instruction implements JUMF IF NOT ZERO and DECREMENT COUNTER structure.
The execution proceeds in the sequence, after the loop is executed, CX number of times. Lf CX is already OOH, the execution continues in sequence. Flags are remaining unaffected by this instruction.
program to arrange a given set of numbers in descending order
The Pentium The next member of the Intel family of microprocessors was the Pentium, introduced in the year 1993. With the Pentium, Intel broke its custom of numeric model name
1. Assembly code for the flow chart we did in the class about the simple I/O interface driver 2. Enhanced driver (flow chart and its assembly code) to cater for interruptions in th
Cache Memory Caching is a technology based on the memory subsystem of any computer. The majoraim of a cache is to accelerate the computer while keeping the cost of the computer
Declare 1 constant. This can be done just below the prototype section. Put the following divider above the constant section. ;************************ Constants ****************
DMA DMA stands for Direct Memory Access It is uses same Address/Data lines on ISA bus It controls the ISA bus instead of the processor ("bus master") Floppy
LIST p=18f4550 #include org 0x0000 movlw 0x00 _________ movlw 0xFF movwf PORTB end .
Program is written but has errors returning values from the procedure.
from pin description it seems that 8086 has 16 address/data lines i.e.AD0_AD15.The physical address is however is larger than 2^16.How this condition can be handled
Ask question #MinimuWHAT ARE CONSTANTS AND WHAT DO THEY DO?m 100 words accepted#
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