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IRET : Return from ISR:-
When an interrupt service routine is called, before transferring control to it, the IP, CS register and flag registers are stored in the stack to mention the location from where the execution is to be continued, after the ISR is executed. Hence, in the ending of each ISR, when IRET is executed, the values of IP, CS register and flags are retrieved from the stack to continue the execution of the main program. The stack is modified consequently.
LOOP : Loop Unconditionally:-
This instruction executes the part of the program from the address or label mention in the instruction up to the loop instruction, CX number of times. Following sequence describe the execution. On every iteration, register CX is decremented automatically. In other terms, this instruction implements JUMF IF NOT ZERO and DECREMENT COUNTER structure.
The execution proceeds in the sequence, after the loop is executed, CX number of times. Lf CX is already OOH, the execution continues in sequence. Flags are remaining unaffected by this instruction.
There are 3 kinds of OCWs. The command word OCWI is utilized for masking the interrupt requests; when the mask bit corresponding to an interrupt request is value 1, then the requ
Flowchart for the sequence of 8251 Whether the control, mode or sync character register is selected depends on the accessing sequence. A flowchart of the sequencing is given i
Assembling a program Microsoft Assembler MASM is one of the simple to use and famous assemblers. All the references and discussions in this section are belonging to the MASM.
AAS: ASCII Adjust AL After Subtraction AAS instruction correct the result in the AL register after subtracting operation of two unpacked ASCII operands. The result is in unpacked
I need help with assembly programing
2. Write a program to separate out positive and negative numbers from a given series of 16-bit hexadecimal numbers.
#question. counters using 8051.
Assembler Directives and Operators The major advantage of machine language programming is directly that the memory control is in the hands of the programmer, so that, he can be
Program : Write an assembly program to find out the largest number from a given unordered array of 8-bit numbers that stored in the locations starting from a known address. S
Comparison between 8086 and 8088 All the changes in 8088 above 8086 are indirectly or directly related to the 8-bit, 8085 compatible data and control bus interface. 1) The p
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