Q. The area of the hysteresis loop of a given magnetic material is 50cm^{2} with the two axes scaled as 1cm = 20AT and 1cm = 50mWb, for 50Hz frequency find the total hysteresis loss
Ans.
Given f = 50 Hz
x = 20, (1cm = 20AT)
y = 50m wb = 0.05wb
So hysteresis loss = xy × Area of (B-H) loop joules/m^{3}/cycle
= 20 × 0.05 × 50
= joules/m^{3}/cycle
Total hysteresis loss = 50 × 50
= 2500 watt