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The square cross sections A and B are shown in Fig Q1, the dimensions b = 80 mm, thickness t = 10 mm. A shear force V is applied at the cross section, calculate the maximum shear stress in the cross sections.
Replace the two parallel forces by single force: Replace the two parallel forces acting on the control lever by a single equivalent force R. Sol.: Since single equ
Magnitude, direction and position of resultant force: Q : A horizontal line PQRS is 12 m long, and PQ = QR = RS = 4m. Forces of 1000, 1500, 1000 and 500 N act at P ,
how to fraw a parabolla in parallelogram
how much of mass lost in between 600-900 c
Loading Conditions Non-uniformity of loading has to be considered in the choice of foundations particularly in highly compressible soils. It is not uncommon for buildings with
OBJECTIVES OF VE: 1. To establishing the monitoring value of the function of the product or services. 2. To identifying unnecessary cost or hidden cost in a product or services.
Concept of continuum - thermodynamics: Sol: Even the simplification of matter into molecules, atoms, electrons, etc. is too complex a picture for many problems of thermodyna
part print analysis
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Describe Nusselt Number, Reynolds Number and Prandtl Number. Get the relation between these three for a circular cylinder losing heat in forced convection to the air flowing around
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