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Q. Explain the odd-even transposition algorithm?
The algorithm needs one 'for loop' beginning from I=1 to N it implies that N times and for every value of I, one 'for loop' of J is executed concurrently. So the time complexity of the algorithm is O(n) because there are total n phases and every phase executes either even or odd transposition in O(1) time.
Figure: Example
Spirit Duplicating Equipment Required Spirit Duplicator (also known as hectograph) Thermal copier (optional) Materials Masters Hectographic carbon COPY pa
Existential Elimination : Now we have a sentence, A, is with an existentially quantified variable, v, so then just for every constant symbol k, that it does not appear anywhe
Consider a network message transfer among a source S and a destination D by 3 routers R1, R2 and R3 as given below:- S -------- R1 --------- R2 --------- R3 ---
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What is parsing? Parsing is the process of analyzing a text, formed of a sequence of tokens, to find out its grammatical structure regarding a specified formal grammar. Parsing
What is non-repudiation? how can it be achieved in designing e-cash based system?
Evaluation Functions: Evaluation functions calculate approximately the score which can be prove of guaranteed if a particular world state is reached. Same like in chess, evalu
Q. How can we write an Interrupt Servicing Routine? The following are the fundamentalthough rigid sequence of steps: 1. Save the system context (flags,registers etc. which
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DETERMINE ANALYTICALY IF THE SIGNAL IS PERIODIC OR NOT - X[n] = 4Cos(Pi n)
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