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Differentiate between pre-emptive and non-pre-emptive scheduling.Pre-emptive scheduling: in its approach, center processing unit can be taken away from a process if there is a require while in a non-pre-emptive approach if one time a process has been specified the CPU, the CPU can't be taken away from such process, unless the process leaves or completes the CPU for performing an Input and Output.Pre-emptive scheduling is more helpful in high priority process that requires immediate response, for illustration in real time system. Whereas in non-preemptive systems, jobs are made to wait through longer jobs, but treatment of each process is fairer.
Explain Implementation techniques Implementation techniques(e.g. remote invocation, HTTP). An event-based cooperation can be executed using message passing or it can be based
Q. Basic Architecture of computer system? Replacing the ALU and CU (i.e., CPU) of Figure by a microprocessor, and storing instructions and data in the same memory, one arrives
explain associative mapping
Q. Initialize new PVM processes? pvm_spawn( char *task, char **argv, int flag, char *where, int ntask, int *tids ) Initialize new PVM processes. Task a character st
Write explanatory notes on Microprocessor development system. Microprocessor development system: Computer systems have undergone many changes recently. Machines which once fi
Which datatype cannot be used to define parameters. Type F datatype is not used to explain parameters.
What is Synchronous reset? Synchronous reset: Synchronous reset logic will synthesize to smaller flip-flops, mainly when the reset is gated along with the logic generating t
Links and Association Links and associations are the basic means used for establishing relationships among objects and classes of the system. In the next subsection we will di
Class is a user-defined data type in C++. It can be formed to solve a particular kind of problem. After creation the user require not know the specifics of the working of a class.
In a two stage network there are 512 inlets and outlets, r=s=24. If the probability that a given inlet is active is 0.8, calculate: the switching elements Given: N =M =512,
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