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Differentiate between pre-emptive and non-pre-emptive scheduling.Pre-emptive scheduling: in its approach, center processing unit can be taken away from a process if there is a require while in a non-pre-emptive approach if one time a process has been specified the CPU, the CPU can't be taken away from such process, unless the process leaves or completes the CPU for performing an Input and Output.Pre-emptive scheduling is more helpful in high priority process that requires immediate response, for illustration in real time system. Whereas in non-preemptive systems, jobs are made to wait through longer jobs, but treatment of each process is fairer.
What is the difference among object oriented and structured oriented programming? Ans) ? Object Oriented means programme will be there in terms of Class and Object connection w
Can a structure be used within a structure? Yes , a structure can be used within a structure known as nesting of structures.
I got a graduate level database assignment which is due at Dec 8, 11:59p.m. Can you finish it on time in high quality?
can u please tell me the assembly language program for carry look ahead adder that can run in 8086 emulator?? its urgent
Is it possible to extract data from tables without using the event 'GET' in the report with an appropriate LDB. False. You can extract data from tables using Select stateme
Problem : (a) The concept of an agent is generally defined by listing the properties that agents exhibit. Identify and describe the properties that you would associate with th
The excess-3 code of decimal 7 is represented by ? Ans. An excess 3 code of decimal 7 is equal to the binary code +3.
Function of an IP Packet Screening Router: A screening router is the most basic type of firewall and uses only the packet filtering capability to control and monitor network tr
The preorder traversal sequence of a binary search tree is 30, 20, 10, 15, 25, 23, 39, 35, 42. Which one of the following is the postorder traversal sequence of the same tree?
Perform multiplication with showing the contents of accumulator, B register and Y register during each step. (Accumulator, B, Y are 4-bit registers) B=06 Y=02
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