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Explain deadlock detection algorithm for single instance of each resource type.
For single instance of each resource type the deadlock detection algorithm:
(i) Maintain a wait: In the graph nodes represent process. If process i is waiting for resource hold through process j. After that there is an edge from I to j.
(ii) Periodically invokes an algorithm which searches for cycles into the graph. If there is a cycle in the wait-for-graph so a dead lock is as exist in the system.
What is software interrupt? A software interrupt is initiated by implementing an instruction. Software interrupt is a special call instruction that behaves like an interrupt
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One Erlang is equal to (A) 3600 CCS (B) 36 CCS (C) 60 CCS (D) 24 CCS Ans: One Erlang is equivalent to 3600 CCS.
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Q. Illustration of parallel programming environments? Let's discuss illustrations of parallel programming environments of Intel paragaon XP/S and Cray Y-MP software. The Cra
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