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Find (dy)/( dx) for;
(i). y = x^{7}
(ii). y = x^{2γ}
(iii). y = x^{-3}
(iv). y = x
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Solution
i. y = x^{7}
(dy)/( dx) = 7x ^{7-1} = 7x^{6}
ii. y = x^{2?}
(dy)/(dx) = 2^{γ} x(2^{γ}- 1)
iii. y = x^{-3}
(dy)/(dx) = -3x^{-3-1} = -3x^{-4}
vi. y = x
(dy)/( dx) = 1x^{1-1} = 1.x^{0}= 1 (since x^{0}=1)
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