Determine the poisson probability distribution, Mathematics

A manufacturer assures his customers that the probability of having defective item is as 0.005. A sample of 1000 items was inspected. Determine the probabilities of having the given possible outcomes

i. Simply one is defective

ii. Mostly 2 defective

iii. More than 3 defective

P(x) =  e λx/x!

(? = np = 1000 × 0.005) = 5

i. P(only one is defective) = P(1) = P(x = 1)

= (2.718-5 * 51)/1!     Note that 2.718-5=  1/(2.718)5

= 5/(2.718)5

= 5/(148.33)

ii. P(at most 2 defective) = P(x ≤ 2)

= P(0) +P(1)+P(2)

P(x=0) = e-550/0!

= 2.718-5

= 1/(2.718)+5

= 0.00674

P(1) = 0.0337

P(2) = (2.718-5 * 52)/2!

= 0.08427

P(x<2) = 0.00674 + 0.0337 + 0.08427

= 0.012471

iii. P(more than 3 defective) = P(x > 3)

= 1 -  [P(0)+P(1)+P(2)+P(3)]

Posted Date: 2/20/2013 6:25:51 AM | Location : United States







Related Discussions:- Determine the poisson probability distribution, Assignment Help, Ask Question on Determine the poisson probability distribution, Get Answer, Expert's Help, Determine the poisson probability distribution Discussions

Write discussion on Determine the poisson probability distribution
Your posts are moderated
Related Questions
recomendation to a company to implement ERP to succeed

In algebra knowing that 2 3 = 8 is not sufficient. Equally important to know is what would be the result if quantities like 2 3 . 2 -4 . 2 6 or  3 7 / 3 2

How do you find the maxima or minima on a parabolic graph?

what is 2+2=

Model of 180 meter tall building using a scale of 1.5 centimeters = 3.5 meters. How tall will the model be?

if theta is a positive acute angle and 2sin theta +15cos square theta=7 then find the value of cot theta

When finding the limit as x approaches 0 the for function (square root of x^3 + x^2) cos(pi/2x) would the limit not exist because there would be a zero in the denominator?

sin (cot -1 {cos (tan -1 x)}) tan -1 x = A  => tan A =x sec A = √(1+x 2 ) ==>  cos A = 1/√(1+x 2 )    so   A =  cos -1 (1/√(1+x 2 )) sin (cot -1 {cos (tan -1 x)}) = s


six men and Eight boys can finish a piece of work in 14 days while  eight men and twelve boys can do it in 10 days. Find the time taken by  1man alone and that by 1boy alone to fin