Determine the forces in strings:
The Electric light fixture weighing 15N hangs from point C, by two strings AC and BC. AC is inclined at 60° to the horizontal and BC at 45° to the vertical as shown in figure given below, Determine the forces in strings AC and BC
Sol.: First draw the free body digram of the electric light fixture, Apply lami's theorem at 'C'
T_{1}/sin 150° = T2/sin 135° = 15/sin75°
T_{1} = 15.sin150°/ sin75°
T_{1} = 7.76N .......ANS
T_{2} = 15.sin135°/ sin75°
T_{2} = 10.98N .......ANS