Chi square distribution, Mathematics

Assignment Help:

Chi Square Distribution

Chi square was first utilized by Karl Pearson in 1900. It is denoted by the Greek letter χ2. This contains only one parameter, called the number of degrees of freedom (d-f), whereas term degree of freedom represents the number of independent random variables that express the chi square

Properties

1. Its critical values vary along with the degree of freedom. For every raise in the number of degrees of freedom there is a new χ2 distribution.

2. This possesses additional property then that when χ21 and χ22 are independent and have a chi square distribution along with n1 and n2 degrees of from χ21 + χ22 will be distributed also as a chi square distribution along with n1 + n2 degrees of freedom

3. Where the degrees of freedom are 3.0 and less the distribution of χ2 is skewed. However, for degrees of freedom greater than 30 in a distribution, the values of χ2 are generally distributed

4. The χ 2 function has simply one parameter, the number of degrees of freedom.

391_Chi Square distribution.png

5. χ2 distribution is a continuous probability distribution that has the value zero at its lower limit and extends to infinity in the positive direction. Negative value of χ2 is not possible since the differences between the expected and observed frequencies are usually squared.


Related Discussions:- Chi square distribution

Find the solution to initial value problem, Illustration:   Find the soluti...

Illustration:   Find the solution to the subsequent IVP. ty' + 2y = t 2 - t + 1,      y(1) = ½ Solution : Initially divide via the t to find the differential equation in

Determine the domain and range of function, Determine the domain of each of...

Determine the domain of each of the following functions.                         f( x ) = x - 4 / x 2 - 2 x -15 Solution With this problem we have to avoid division by

Student, What is the slope and y intercept for (6,5) (-3,8)

What is the slope and y intercept for (6,5) (-3,8)

If oa = ob = 14cm, If OA = OB = 14cm, ∠AOB=90 o , find the area of shaded r...

If OA = OB = 14cm, ∠AOB=90 o , find the area of shaded region.  (Ans:21cm 2 ) Ans:    Area of the shaded region = Area of ? AOB - Area of Semi Circle = 1/2  x 14 x

Sketch the graph f ( x ) = - x5 + (5/2 )x4 + (40/3) x3 + 5, Sketch the grap...

Sketch the graph of the below function. f ( x ) = - x 5 + (5/2 )x 4 + (40/3) x 3 + 5 Solution : Whenever we sketch a graph it's good to have a few points on the graph to

Reduction of order, We're here going to take a brief detour and notice solu...

We're here going to take a brief detour and notice solutions to non-constant coefficient, second order differential equations of the form. p (t) y′′ + q (t ) y′ + r (t ) y = 0

Linear equations, Linear Equations We'll begin the solving portion of ...

Linear Equations We'll begin the solving portion of this chapter by solving linear equations. Standard form of a linear equation: A linear equation is any equation whi

Explain the decimal system in detail, Explain The Decimal System in detail?...

Explain The Decimal System in detail? A decimal, such as 1.23, is made up of two parts: a whole number and a decimal fraction. In 1.23, the whole number is 1 and the decimal fr

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd