Calculate for spring amount of load carried, Mechanical Engineering

Calculate for spring amount of load carried:

The table below gives specific of a compound spring consisting of two co-axial close-coiled springs. If the spring is subjected to an axial load of 450 N, calculate for each spring

a. the change in length,

b. the amount of load carried, and

c. the maximum shearing stress.

Take G = 80 × 103 N/mm2.

387_Calculate for spring amount of load carried.png


The free length of outer spring is more than the inner spring by (100 - 80) = 20 mm. Load carried through the outer spring for a deflection of 20 mm is specified by,

Δ= 64 W R3 n / Gd 4

⇒ 20 =     64 × W × 253 × 10 / (80 × 103 × 54)

∴ W1  = 100 N

Now the springs are in parallel. Load to be shared by the two springs

= 450 - 100 = 350 N

Δ= 64 W R3 n / Gd 4

2069_Calculate for spring amount of load carried1.png----------(1)

1435_Calculate for spring amount of load carried2.png

     2397_Calculate for spring amount of load carried3.png  ---------(2)

377_Calculate for spring amount of load carried4.png

⇒         5 Δ + 11.9 Δ= 350

∴          Δ= 20.7 mm

Change in length, Δ= 20.7 mm

1219_Calculate for spring amount of load carried5.png

Load taken by outer spring = 203.5 N.

Load taken by inner spring = 246.5 N.

τ max  =   16 W R  / π d 3

τmax is outer spring =   16 × 203.5 × 25/( π× 53) = 207.3 N/mm

τmax in inner spring =16 × 246.5 × 15/( π× 43) = 294.2 N/mm

∴ Maximum shearing stress = 294.2 N/mm2 (inner spring).

Posted Date: 1/21/2013 1:51:47 AM | Location : United States

Related Discussions:- Calculate for spring amount of load carried, Assignment Help, Ask Question on Calculate for spring amount of load carried, Get Answer, Expert's Help, Calculate for spring amount of load carried Discussions

Write discussion on Calculate for spring amount of load carried
Your posts are moderated
Related Questions
The de-oiled water from De-Oiling Unit enters the HLS vessel for softening. The primary function of HLS is to remove the Ca and Mg hardness and bring the total hardness to less tha

Determine root of equation xe x = cosx by Muller's method. Solve the following equations by Matrix Inversion method.

Force on String: A string ABCD , attached to the two fixed points A and D has two weight of 1000N each attached to it at points B and C . The weights rest with portio

Working of Engine Lubrication System: The oil flows from oil pump into the distribution chamber, where it is divided into two parts. One part enters into the right crankcase cove

Evaluate power transmitted by belt.  Sol: Let T 1  = Tension in tight side of the belt T 2 = Tension in slack side of the belt V = Velocity of belt in m/sec.  = Π

Ease of Operation : For higher power transmissions, the operation of disengaging the clutch must not be tiresome to the driver.

Find out the motion of the system: Block (A) of mass M A = 40 kg is resting on coarse table having coefficient of friction = 0.1. This is tied up with an inextensible rope (

Evaluate resultant of the system: Q: Figure given below shows two vertical forces and couple of moment 2000 Nm acts on horizontal rod, which is fixed at end A .  Determin

vacuum gauge indicates that the pressure of air in a closed chamber is 0.2bar(vacuum).The pressure of the surrounding atmosphere is equilent to a 750-mm column of mercury.The densi