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The physical memory acts as a cache backed by the disk. When the physical memory is full, and we want to read in another page from disk, we have to evict a page from physical memory. How do we choose which page to evict? This is determined by the cache replacement policy. Note that in a theoretical algorithms course, you are generally interested in the worst-case asymptotic performance of an algorithm. In building systems, worst-case performance can be important (for instance, in systemswith real-time requirements), but oftenwe canmost about the algorithm's performance for the most common case. If a particular algorithm has good worst-case performance, but bad common-case performance, it is a bad algorithm.
about error detection in operating system and how does it take place?
Q. Illustrate Scope of Consumer behaviour ? Scope of consumer behaviour is extremely wide due to following reasons: >>Ever rising intensifying competition. >>Additional a
What is super block A partition control block have partitions details, such as the number of blocks in the partition, size of the blocks, free-blocks and free-block pointers an
Demand paging With demand paging, a page is called into memory only when a location on that page is actually indexed during run time. With pre-paging, pages other than the one
Parent and Child process communicate in unix A child and parent can interact through any of the normal inter-process communication schemes (pipes, message queues, sockets, s
Question: (a) The following table (table 1.0) gives the length of the CPU burst time in milliseconds of processes P 1 to P 4 . Assume the processes arrived in the order P 1 ,
Grouping Threads That Execute Similar Functions Thread Groups are generally used to group threads that execute similar functions of the application program. For instance, if
case study:interprocess communication
FIXED PARTITIONING Using fixed partitioning we are able to allocate the memory Here we are dividing the memory into a few fixed partitions.Every partition may not be of the si
Q. Explain a mechanism by which one segment could belong to the address space of two different processes. Answer: Because segment tables are a collection of base-limit register
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