Bolter - thermodynamics, Mechanical Engineering

Bolter:

(kE2  - kE1) = 0, (pE2  - pE1) = 0, w1-2  = 0

Now,  q1-2 = w1-2  (h2  - h1) + (kE2  - kE1) + (pE2  - pE1)

q1-2 = h2  - h1

Heat supplied in boiler increases the enthalpy of system.

2431_Bolter.png

 q1-2 = w1-2 (h2  - h1) + (kE2  - kE1) + PE2  - pE1) - q1-2 = h2 - h1

Heat energy is lost by the system to the cooling water

q1-2 = h1  - h2

 

Posted Date: 10/15/2012 2:47:22 AM | Location : United States







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