Already have an account? Get multiple benefits of using own account!
Login in your account..!
Remember me
Don't have an account? Create your account in less than a minutes,
Forgot password? how can I recover my password now!
Enter right registered email to receive password!
We are use to using variables within C without thinking about where they are stored. Most variables are dynamic i.e. can change, therefore they are stored in Ram, unlike a program once developed is static i.e. doesn't change; this is often storage in EPROM or Rom. We can directly access the address where the variable is stored by means of the address operator '&' .This returns the address of the variable followed i.e.
printf("The address of var A is %lx and the contents of var A is %x",&a,a) This address is often fixed by the compiler and cannot be altered easily, very often we want initialize the address of a variable and vary it, C uses the concept of the pointer to handle this. A pointer is a variable which holds an address (This is in fact an address register on the 68Hc11 i.e. X, Y). We can explicitly load up the variable with any number (address which we like) and perform simple mathematical functions on it i.e. add, mul, sub etc. In order to declare the variable as a pointer we need to prefix it with a * in its declarations i.e.
int *point; char *point; float *point;
The type of pointer used describes the size of the data to be read i.e. a char pointer reads 7 bits of data , unsigned char 8 bits i.e. (some programmers use sizeof function to get actual machine size).
char * point == 7 bits unsigned char * point == 8 bits int * point == 15 bits unsigned int * point == 16 bits float * point == 31 bits unsigned float * point == 32 bits
combined approaches (ULT/KLT)
write a linux command to display lines from 25 - 45 of directory "/edc/password" write a linux command to display directory in /edc
What are the requirements to be satisfied by the critical section problem? Following are the necessities to be satisfied by the critical section problem: a) Mutual exc
Q. Consider the two-dimensional array A: int A[][] = new int[100][100]; Whereas A [0][0] is at location 200 in a paged memory system with pages of size 200. A little process
Problem: (a) Modern operating systems are interrupt driven. If there are no processes to execute, no I/O devices to service, and no users to whom to respond, an operating syste
how do semaphores help us in eliminating deadlock conditions?
COMPARISON OF DISK SCHEDULING ALGORITHMS Name Description Remarks (Selection according to requestor) RSS Random scheduling fo
THE PROGRAM WILL CHOOSE TWO RANDOM NUMBERS,THEN PRINT THEM OUT AS AN ADDITION PROBLEM.THE PROGRAM WILL THEN ASK THE USERTO ENTER THE CORRECT ANSWER.IF THE ANSWER IS CORRECT,THE PRO
SEGMENTATION HARDWARE An execution to map two-dimensional user-defined addresses into one-dimensional physical addresses. This mapping is affected by means of segment table. Ev
explain in detail about ipc in linux
Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!
whatsapp: +91-977-207-8620
Phone: +91-977-207-8620
Email: [email protected]
All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd