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Y=θ[SIN(INθ)+COS(INθ)],THEN FIND dy÷dθ.
Solution) Y=θ[SIN(INθ)+COS(INθ)]applying u.v rulethen dy÷dθ={[ SIN(INθ)+COS(INθ) ] dθ÷dθ }+ {θ[ d÷dθ{SIN(INθ)+COS(INθ) ] } => SIN(INθ)+COS(INθ) + θ{ (COS(INθ)÷ θ) - (SIN(INθ)÷θ) } θ is canceled and sin(ln θ ) is also canceled then u will get => 2COS(INθ)
2qt :6qt::x :48? help me solve x
Product and Quotient Rule : Firstly let's see why we have to be careful with products & quotients. Assume that we have the two functions f ( x ) = x 3 and g ( x ) = x 6 .
Using the example provided below, if the measure ∠AEB = 5x + 40 and ∠BEC = x + 20, determine m∠DEC. a. 40° b. 25° c. 140° d. 65° c. The addition of the measurem
(i may have spelled it wrong)but i forgot how to do them.
Explain Angle Theorems ? Certain angles and angle pairs have special characteristics: Vertical angles are opposite angles formed by the intersection of two lines. Vertical ang
Set M= {m''s/m is a number from 5 to 10}
Two sessions of swimming lessons were held at a pool. In the first session 40 students attended. Of these 40 students 60% were girls. How many girls attended the first session of s
use the expansion of (1-x)^7 to find the value of 1.998^7 correct to five significant figures
for all real numbers x, x 0
Solve the following Linear Programming Problem using Simple method. Maximize Z= 3x1 + 2X2, Subject to the constraints: X1+ X2 = 4 X1+ X2 = 2 X1, X2 = 0
y=Θ[sin(lnΘ)+cos(lnΘ)] dy/dΘ=[sin(lnΘ)+cos(lnΘ)] + Θ[cos(lnΘ)-sin(lnΘ)]*1/Θ ---->(Use Multiplication rule) dy/dΘ=2cosΘ.
y=Θ[sin(lnΘ)+cos(lnΘ)]
dy/dΘ=[sin(lnΘ)+cos(lnΘ)] + Θ[cos(lnΘ)-sin(lnΘ)]*1/Θ ---->(Use Multiplication rule)
dy/dΘ=2cosΘ.
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