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Y=θ[SIN(INθ)+COS(INθ)],THEN FIND dy÷dθ.
Solution) Y=θ[SIN(INθ)+COS(INθ)]applying u.v rulethen dy÷dθ={[ SIN(INθ)+COS(INθ) ] dθ÷dθ }+ {θ[ d÷dθ{SIN(INθ)+COS(INθ) ] } => SIN(INθ)+COS(INθ) + θ{ (COS(INθ)÷ θ) - (SIN(INθ)÷θ) } θ is canceled and sin(ln θ ) is also canceled then u will get => 2COS(INθ)
There isn't actually a whole lot to this section this is mainly here thus we can get several basic concepts and definitions out of the way. Most of the concepts and definitions in
Find the probability of having 53 Sundays in (i) a leap year (ii) a non leap year (Ans:2/7 , 1/7 ) Ans: An ordinary year has 365 da
Jonestown High School has a soccer field whose dimensions can be expressed as 7y 2 and 3xy. What is the area of this field in terms of x and y? Since the area of the soccer ?e
what are these all about and could i have some examples of them please
Consider x € R. Then the magnitude of x is known as it's absolute value and in general, shown by |x| and is explained as Since the symbol always shows the nonnegative
x+2y^2=63 and 4x+y^2=0; Find the area of the regions enclosed by the lines and curves.
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A car travels 283 1/km in 4 2/3 hours .How far does it go in 1 hour?
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y=Θ[sin(lnΘ)+cos(lnΘ)] dy/dΘ=[sin(lnΘ)+cos(lnΘ)] + Θ[cos(lnΘ)-sin(lnΘ)]*1/Θ ---->(Use Multiplication rule) dy/dΘ=2cosΘ.
y=Θ[sin(lnΘ)+cos(lnΘ)]
dy/dΘ=[sin(lnΘ)+cos(lnΘ)] + Θ[cos(lnΘ)-sin(lnΘ)]*1/Θ ---->(Use Multiplication rule)
dy/dΘ=2cosΘ.
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