Y=Theea[sin(inTheeta)+cos(inTheeta)],then find dy÷dTheeta, Mathematics

Assignment Help:

Y=θ[SIN(INθ)+COS(INθ)],THEN FIND dy÷dθ.

Solution)  Y=θ[SIN(INθ)+COS(INθ)]

applying u.v rule

then dy÷dθ={[ SIN(INθ)+COS(INθ) ] dθ÷dθ }+ {θ[ d÷dθ{SIN(INθ)+COS(INθ) ] }

   => SIN(INθ)+COS(INθ) + θ{ (COS(INθ)÷  θ) - (SIN(INθ)÷θ) }

   θ is canceled and  sin(ln θ ) is also canceled  then u will get
   =>  2COS(INθ)


Related Discussions:- Y=Theea[sin(inTheeta)+cos(inTheeta)],then find dy÷dTheeta

Differentiate inside function in chain rule, Differentiate following. f ...

Differentiate following. f ( x ) = sin (3x 2   + x ) Solution It looks as the outside function is the sine & the inside function is 3x 2 +x. The derivative is then.

Math, i have problems with math and my teacher said that i am still progres...

i have problems with math and my teacher said that i am still progressing in math

Vectors, A plane is flying at 200 mph with a heading of 45degrees and encou...

A plane is flying at 200 mph with a heading of 45degrees and encounters a wind mph from the west. What is the velocity and heading?

Math on a spot, compare: 643,251: 633,512: 633,893. The answer is 633,512.

compare: 643,251: 633,512: 633,893. The answer is 633,512.

Phase transformations in binary system, Get the Delta H (Enthalpy) and Delt...

Get the Delta H (Enthalpy) and Delta V (Volume) of the both components below and compare by ratio.  You need to use clapeyron equation and also need to draw the graphs. S A LG

3/11/2013 12:59:09 AM

y=Θ[sin(lnΘ)+cos(lnΘ)]

dy/dΘ=[sin(lnΘ)+cos(lnΘ)] + Θ[cos(lnΘ)-sin(lnΘ)]*1/Θ ---->(Use Multiplication rule)

dy/dΘ=2cosΘ.

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd