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Y=θ[SIN(INθ)+COS(INθ)],THEN FIND dy÷dθ.
Solution) Y=θ[SIN(INθ)+COS(INθ)]applying u.v rulethen dy÷dθ={[ SIN(INθ)+COS(INθ) ] dθ÷dθ }+ {θ[ d÷dθ{SIN(INθ)+COS(INθ) ] } => SIN(INθ)+COS(INθ) + θ{ (COS(INθ)÷ θ) - (SIN(INθ)÷θ) } θ is canceled and sin(ln θ ) is also canceled then u will get => 2COS(INθ)
how to Multiplying Rational Expressions ? To multiply fractions, or rational expressions, you must multiply the numerators and then multiply the denominators. Here's how it is
20 equations that equal 36
If α,β are the zeros of the polynomial 2x 2 - 4x + 5 find the value of a) α 2 + β 2 b) (α - β) 2 . Ans : p (x) = 2 x 2 - 4 x + 5 (Ans: a) -1 , b) -6) α + β =
I need help converting my project fractions into 1
jenna asked 100 of her schoolmates if they have had their first kiss and 43 of them said yes
when one side of a triangle is 15cm and the bottom of the triangle is 12cm what would x be rounded to the nearest tenth?
The value of y is among negative three and positive eight inclusive. Which of the subsequent represents y? This inequality displays a solution set where y is greater than or eq
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6 muliplied by 2
y=Θ[sin(lnΘ)+cos(lnΘ)] dy/dΘ=[sin(lnΘ)+cos(lnΘ)] + Θ[cos(lnΘ)-sin(lnΘ)]*1/Θ ---->(Use Multiplication rule) dy/dΘ=2cosΘ.
y=Θ[sin(lnΘ)+cos(lnΘ)]
dy/dΘ=[sin(lnΘ)+cos(lnΘ)] + Θ[cos(lnΘ)-sin(lnΘ)]*1/Θ ---->(Use Multiplication rule)
dy/dΘ=2cosΘ.
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