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Write a program to compute the following equation for values of time. y = 2x+3 The values of time are stored in the file program.dat and the solution should be displayed on the screen and stored in a file called program.out. Answer #include stdio.h #include stdlib.h void main() { char prompt; Date: 26th August 2012 Version 1.0 Function : ASCII file handling Modifications: none*/ /* Define I/O streams */ FILE *fptr,*fptw; float x,y; fptr = fopen("program.dat","r");
if (fptr == NULL) { /* Check for error */ printf("Cannot find the file program.dat\n\r"); exit(1); } fptw = fopen("program.out","w"); if (fptw == NULL) { /* Check for error */ printf("Cannot create a new file called program.out"); fclose(fptr); exit(1); } while (fscanf(fptr,"%f",&x) != EOF) { /* This repeats the read till fscanf returns back an End of file marker i.e No data left */ y = 2*x+3; printf("X = %f Y=%f\n\r",x,y); fprintf(fptw,"X = %f Y=%f\n\r",x,y); } printf("I have finished the computation\n\r"); fclose(fptr); fclose(fptw); printf("Press and key to exit \n\r"); scanf("\n%c",&prompt); } Original data can be entered using the application 'NOTEPAD', or 'Edit' likewise the output can be read by Notepad or any word processor set to text mode.
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Run the following C++ program with and without preprocessor variable POSTFIX defined. #include using namespace std; extern "C" int atoi( const char *str );
A string S is said to be "Super ASCII", if it contains the character frequency equal to their ascii values. String will contain only lower case alphabets (''a''-''z'') and the asci
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(a) Write a procedure (count-even n) that counts the number of even digits in the decimal representation of the number n. For example, (count-even 234) should return 2. (b) Writ
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