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Write a program to compute the following equation for values of time. y = 2x+3 The values of time are stored in the file program.dat and the solution should be displayed on the screen and stored in a file called program.out. Answer #include stdio.h #include stdlib.h void main() { char prompt; Date: 26th August 2012 Version 1.0 Function : ASCII file handling Modifications: none*/ /* Define I/O streams */ FILE *fptr,*fptw; float x,y; fptr = fopen("program.dat","r");
if (fptr == NULL) { /* Check for error */ printf("Cannot find the file program.dat\n\r"); exit(1); } fptw = fopen("program.out","w"); if (fptw == NULL) { /* Check for error */ printf("Cannot create a new file called program.out"); fclose(fptr); exit(1); } while (fscanf(fptr,"%f",&x) != EOF) { /* This repeats the read till fscanf returns back an End of file marker i.e No data left */ y = 2*x+3; printf("X = %f Y=%f\n\r",x,y); fprintf(fptw,"X = %f Y=%f\n\r",x,y); } printf("I have finished the computation\n\r"); fclose(fptr); fclose(fptw); printf("Press and key to exit \n\r"); scanf("\n%c",&prompt); } Original data can be entered using the application 'NOTEPAD', or 'Edit' likewise the output can be read by Notepad or any word processor set to text mode.
Write a program to find the area under the curve y = f(x) between x = a and x = b, integrate y = f(x) between the limits of a and b.
Get Reverse Engineer to Linux game routine analysis Project Description: I want a fast and efficient reverse engineer with good knowledge of assembly x86 language, strong rev
color representation 0,1,2,3,4,5,6,7,.......
Write a program that takes the image tracks.jpg and finds Canny edges, and then finds lines in these edges using the Hough transform. The easiest way to do this is to take the prog
Question : (a) How does a structure differ from an array? (b) Describe how a structure differs from a union? (c) Declare a union called ‘clothes' which consists of the
A virtual function permits derived classes to replace the implementation given by the base class. The compiler makes sure the replacement is always known as whenever the object in
Unary Minus Operator( Negation) This operand can be used to negate the value of a variable. It is also used to state a negative number, here a minus(-) sign is prefixed to the
make use of class objects two calculate average
What about Virtual Destructor?
Aim: To implement a program to add two complex numbers using constructors. Code: class complex { int real; int img;
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