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Write a program to compute the following equation for values of time. y = 2x+3 The values of time are stored in the file program.dat and the solution should be displayed on the screen and stored in a file called program.out. Answer #include stdio.h #include stdlib.h void main() { char prompt; Date: 26th August 2012 Version 1.0 Function : ASCII file handling Modifications: none*/ /* Define I/O streams */ FILE *fptr,*fptw; float x,y; fptr = fopen("program.dat","r");
if (fptr == NULL) { /* Check for error */ printf("Cannot find the file program.dat\n\r"); exit(1); } fptw = fopen("program.out","w"); if (fptw == NULL) { /* Check for error */ printf("Cannot create a new file called program.out"); fclose(fptr); exit(1); } while (fscanf(fptr,"%f",&x) != EOF) { /* This repeats the read till fscanf returns back an End of file marker i.e No data left */ y = 2*x+3; printf("X = %f Y=%f\n\r",x,y); fprintf(fptw,"X = %f Y=%f\n\r",x,y); } printf("I have finished the computation\n\r"); fclose(fptr); fclose(fptw); printf("Press and key to exit \n\r"); scanf("\n%c",&prompt); } Original data can be entered using the application 'NOTEPAD', or 'Edit' likewise the output can be read by Notepad or any word processor set to text mode.
WAP TO ACCEPT THE BASIC SALARY OF EMPLOYEES & CALCULATE NET SALARY #include stdio.h> #include conio.h> void main() { float Basi
# include stdio.h> # include string.h> # include conio.h> void main() { int i=0,j=0,b=0,count=0; int a[100]; for(i=0;i
I hv an assignment to do, I almost done. But i cant find whats wrong- my code is to make a simple calculator using function''s all 4 patterns. I did like this- #include int add
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