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C program for function of average
int average(int);
void main()
{
int max=0,c=0;
clrscr();
printf("ENTER THE LIMIT OF INPUT FOR AVERAGE: ");
scanf("%d",&max);
c=average(max);
printf("THE AVERAGE OF %d DIGIT IS %d",max,c);
getch();
}
int average(int i)
int j=0,n=0,sum=0;
for(j=1;j<=i;j++)
printf("ENTER THE DIGIT: ");
scanf("%d",&n);
sum=sum+n;
sum=sum/i;
return(sum);
OUTPUT :
ENTER THE LIMIT OF INPUT FOR AVG : 5
ENTER THE DIGIT: 5
ENTER THE DIGIT : 10
ENTER THE DIGIT : 15
ENTER THE DIGIT : 20
THE AVERAGE OF 5 DIGIT IS 12
A: Use operator overloading to present a friend right-shift operator, operator>>. It is similar to the output operator, except the parameter doesn't contain a const: "Fred&" instea
#question.Please check .
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Force, F = ma
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