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C program for function of average
int average(int);
void main()
{
int max=0,c=0;
clrscr();
printf("ENTER THE LIMIT OF INPUT FOR AVERAGE: ");
scanf("%d",&max);
c=average(max);
printf("THE AVERAGE OF %d DIGIT IS %d",max,c);
getch();
}
int average(int i)
int j=0,n=0,sum=0;
for(j=1;j<=i;j++)
printf("ENTER THE DIGIT: ");
scanf("%d",&n);
sum=sum+n;
sum=sum/i;
return(sum);
OUTPUT :
ENTER THE LIMIT OF INPUT FOR AVG : 5
ENTER THE DIGIT: 5
ENTER THE DIGIT : 10
ENTER THE DIGIT : 15
ENTER THE DIGIT : 20
THE AVERAGE OF 5 DIGIT IS 12
Described virtual destructor?
A: Mostly can be overloaded. The only C operators which can't be are. and?: (and sizeof, that is technically an operator). C++ adds a few of its own operators, mostly which can be
P o i n t e r d e c l a r a t i o n f o r me m b e r f un c t i o n : M e t h o d 1 : W h e n C l a ss i s n o t
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