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C program for function of average
int average(int);
void main()
{
int max=0,c=0;
clrscr();
printf("ENTER THE LIMIT OF INPUT FOR AVERAGE: ");
scanf("%d",&max);
c=average(max);
printf("THE AVERAGE OF %d DIGIT IS %d",max,c);
getch();
}
int average(int i)
int j=0,n=0,sum=0;
for(j=1;j<=i;j++)
printf("ENTER THE DIGIT: ");
scanf("%d",&n);
sum=sum+n;
sum=sum/i;
return(sum);
OUTPUT :
ENTER THE LIMIT OF INPUT FOR AVG : 5
ENTER THE DIGIT: 5
ENTER THE DIGIT : 10
ENTER THE DIGIT : 15
ENTER THE DIGIT : 20
THE AVERAGE OF 5 DIGIT IS 12
If an array holds integer, each of which is four bytes long, how many bytes from the base location of the array is the location of the fifth element?
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