Already have an account? Get multiple benefits of using own account!
Login in your account..!
Remember me
Don't have an account? Create your account in less than a minutes,
Forgot password? how can I recover my password now!
Enter right registered email to receive password!
Write a M68000 assembly language subroutine MULSUM that takes an array named A containing n bytes of positive numbers, and fills two arrays, array B containing n words and array C containing n long words as follows:
Sum = 0;
for(i = 0; i) Sum = A[i] + Sum; if(Sum is an EVEN number) then
B[i] = Sum; else C[i] = Sum * A[i]; end if end for
In evaluating the expression Sum * A[i] you are NOT allowed to use the MULTU, or MULTS instructions, hence, you are to find another way to calculate this expression.
Main program along with data section is shown below. This program passes all the required parameters to subroutine MULSUM by pushing them on stack.
Note: There is no overflow occurring during any operation.
a) Write the main program
b) Write the subroutine MULSUM
c) Show the stack frame for entire program and clearly label SP at different stages of program.
Ask question #Minimum 250 words accepted#
how to find out the given number is positive or negative?
OR: Logical OR: The OR instruction carries out the OR operation in the similar way as described in case of the AND operation. The restriction on source and destination operands ar
a pseudo-code to add username and password combination up to a limit of 10
AAD: ASCII Adjust for Division though the names of these 2 instructions (AAM and AAD) seem to be same, there is many difference between their functions. The AAD instruction conver
I need to generate a random number bby using 8086 assembly language
Read Architecture: Look Through Main memory that located is conflicting the system interface. The least concerning feature of this cache unit is that it remain between the proc
Pin functions for the minimum mode operation of 8086 are following: 1) M/I/O -Memory/IO: This is a status line logically equivalent to S2 in maximum mode. When it is low, it
Flag Register : 8086 has a 16-bit flag register which is divided into 2 parts, viz. (a)machine control flagsand (b)condition code or status flags. The condition code flag regi
1. Start your program at address $8500. To do this you need to inform the assembler, through the EQU and ORG assembler directives, that you want your program to start at $8500. Thi
Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!
whatsapp: +91-977-207-8620
Phone: +91-977-207-8620
Email: [email protected]
All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd