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Write a M68000 assembly language subroutine MULSUM that takes an array named A containing n bytes of positive numbers, and fills two arrays, array B containing n words and array C containing n long words as follows:
Sum = 0;
for(i = 0; i) Sum = A[i] + Sum; if(Sum is an EVEN number) then
B[i] = Sum; else C[i] = Sum * A[i]; end if end for
In evaluating the expression Sum * A[i] you are NOT allowed to use the MULTU, or MULTS instructions, hence, you are to find another way to calculate this expression.
Main program along with data section is shown below. This program passes all the required parameters to subroutine MULSUM by pushing them on stack.
Note: There is no overflow occurring during any operation.
a) Write the main program
b) Write the subroutine MULSUM
c) Show the stack frame for entire program and clearly label SP at different stages of program.
Explain the architecture of the file transfer protocol ftp in terms of clients, servers, sockets
ADD: Add :- This instruction adds an immediate contents of a memory location specified in the a register ( source ) or instruction to the contents of another register (destinat
OR: Logical OR: The OR instruction carries out the OR operation in the similar way as described in case of the AND operation. The restriction on source and destination operands ar
need help
DAS: Decimal Adjust after Subtraction:- This instruction converts the result of subtraction operation of 2 packed BCD numbers to a valid BCD number. The subtraction operation has
Declare 1 constant. This can be done just below the prototype section. Put the following divider above the constant section. ;************************ Constants ****************
Write an assembly program that will compute and output tuition cost: a. accept keyboard input of the number of credit hours taken b. accept keyboard input of the type of classes 1
Program is written but has errors returning values from the procedure.
DAA: Decimal Adjust Accumulator:- This instruction is utilized to convert the result of the addition operation of 2 packed BCD numbers to a valid BCD number. The conclusion has to
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