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Under the action of constant force, a 2kg block moves such that its position x as a function of time is given by X=t^3/3 ,where x in meters and t in sec , the workdone by force in first 2 seconds isA 26.6 jB 3.3 jC 16 jD 32 jSolution) v=dx/dt=t^2,a=dv/dt=2t,f(t)=ma(t),w=∫f(t)*v(t) dt (from x=0 to x=2 sec)
Prove energy is a property of system
applications of parallelogram
(a) Illustrate the concept of absolute thermodynamic temperature scale on the basis of second law. (b) In a Steady flow apparatus , 13.5 KJ of work is done by each kg of fluid.
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INTRODUCTION: In the previous unit, you studied about the motorcycle and its various parts and systems. In this unit, we shall learn the various aspects of Entrepreneurship Develo
How we say that motion of the follower is simple harmonic motion describe in practical approch
law of belting
cases of equilibrium with explaination
what is a deficient frame?
The hardened layer depth is the measure of harden-ability. A good harden-ability will sense even thicker sections are uniformly hardened. Conversely a poor harden-ability will gene
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