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Work : It is the last application of integral which we'll be looking at under this course. In this section we'll be looking at the amount of work which is done through a force in moving an object.
Under a first course in Physics you classically look at the work as a constant force F, does while moving an object over a distance of d. In such cases the work,
W = Fd
Though, most forces are not constant and will depend upon in which exactly the force is acting. Therefore, let's assume that the force at any x is specified by F(x). Afterward the work complete by the force in moving an object from x = a to x = b is specified by,
Consider that if the force is constant we find the correct formula for a constant force.
Here b-a is only the distance moved or d.
Therefore, let's take a look at a couple of illustration of non-constant forces.
If r,R denote position vectors of points on the straight lines in the direction of a and b respectively, and if n is a unit vector perpendicular to both these directions, show that
1+1
1. Suppose the arrival times of phone calls in a help centre follow a Poisson process with rate 20 per hour (so the inter-arrival times are independent exponential random variables
1/2 + 2/8 =
FORMULAS DERIVATION
monomet
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