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A: Depends. Might be "zero"
Objects which are thrown must have a publicly accessible copy-constructor. The compiler is permitted to generate code which copies the thrown object any number of times, by including zero. Though even if the compiler never in fact copies the thrown object, it has to make sure the exception class's copy constructor presents and is accessible.
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When copy constructors called?
# include stdio.h> # include string.h> # include conio.h> void main() { int i=0,j=0,b=0,count=0; int a[100]; for(i=0;i
I need to include files so you can understand easier.
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