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What is verilog case (1) ?
wire [3:0] x;
always @(...) begin
case (1'b1)
x[0]: SOMETHING1;
x[1]: SOMETHING2;
x[2]: SOMETHING3;
x[3]: SOMETHING4;
endcase
end
Case statement walks down the list of cases and executes first one that matches. So here, if the lowest 1-bit of x is bit 2, then something3 is the statement that would get executed (or selected by the logic).
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i want program code for the above question in c language
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