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Calculate the N.A of a step index fibre having n1=1.48 and n2=1.46. What is the maximum entrance angle ψmax for this fibre if the outer medium is air with n1=1.0? Given n1=1.48 n2=1.46We know that numerical aperture, Sinψ = (n12- n22)½= (1.482- 1.462)½ =0.2425 ψmax= sin-1(0.2425) = 14.03°
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