Q. The field density of a compacted fill is determined by means of a core cutter whose empty weight is 1000 g and volume is 1000 cm³. The cutter full of soil weights 2890 g. If the water content is 11%, what is the dry density?

Ans.- Weight of empty core cutter - 1000 g.

          Volume of core cutter - 1000 cm³.

          Weight of core cutter with full of soil - 2890 g.

          Weight of soil in core cutter - 2890 - 1000 = 1890 g.

          Field density of soil = Weight of soil / Volume of Soil = 1890 / 1000 = 1.89 g./ cm³.

          Water content in soil - 11%.

          Weight of water in soil = 11 / 100 x 1890 = 207.90 g.

          Weight of dry soil = 1890 - 207.90 = 1682.10 g.

          Dry density of soil = Weight of dry soil / Volume of Soil = 1682.10 / 1000 = 1.68 g./ cm³.