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What is the difference between the following two lines of Verilog code?
#5 a = b; a = #5 b;
#5 a = b; Wait five time units before doing the action for "a = b;". Value assigned to a will be the value of b 5 time units hence.
a = #5 b; Value of b is calculated and stored in an internal temp register. After five time units, assign this stored value to a.
What are the basic steps needed to execute an instruction by the processor? Ans: The basic steps needed to execute an instruction by the processor are: A) First fetch th
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