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What is busy waiting?
When strict alteration is done there may take place situation like two processes setting their flag as true. Therefore both of the processes have equal priority to enter into the critical section. Consider that Pi is setting its flag as true in addition to that time a context switch take place so that Pj also sets it flag. Like a result both of them will try to get into the critical section. Therefore neither of them get into the critical section. This circumstance is known as busy waiting. To resolve this Peterson's solution is used.
Parent process P creates three child processes, C1, C2, and C3. Each child process executes a memory and CPU intensive application of your choice. Your choice should be such that
Consider a scenario of post mailbox, there are two processes named sender S and receiver R. Both processes can communicate with each other by name along with message. You need to I
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why we say " OS is a resource allocator" and “OS is a control program"?
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How can the deadlock be prevented Bankers algorithm : The Resource allocation graph algorithm isn't applicable to a resource allocation system with multiple instances of every
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