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What is busy waiting?
When strict alteration is done there may take place situation like two processes setting their flag as true. Therefore both of the processes have equal priority to enter into the critical section. Consider that Pi is setting its flag as true in addition to that time a context switch take place so that Pj also sets it flag. Like a result both of them will try to get into the critical section. Therefore neither of them get into the critical section. This circumstance is known as busy waiting. To resolve this Peterson's solution is used.
We are faced with three major components of the page-fault service time. 1. Service the page-fault interrupts. 2. Read in the page. 3. Restart the processes.
What is an acyclic graph? A tree that has been corrupted by links to other branches, but does not have any cyclic paths in it.
DESIGN GOALS OF WINDOWS XP.DESCRIBE IN DETAIL.
explain any four types of operating system feature and structure(design)
Q. Presume that a system is in an unsafe state. Illustrate that it is possible for the processes to complete their execution without entering a deadlock state. Answer: An unsaf
How can the deadlock be prevented-Safe State Safe state : A state is safe if the system is able to allocate resources to each process in some order and still avoid deadlock.
fork and join syntax in java
Write a short note about the different STATES of a process. As a process implement it changes state. The state of a process is described in part by the current activity of that
Define entry section and exit section. The critical section problem is to design a protocol that the processes can use to cooperate. Every process must request permission to e
Determine a scheduling policy that is most suitable for a time-shared operating system Round-Robin is a scheduling policy that is most suitable for a time-shared operating s
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