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What is busy waiting?
When strict alteration is done there may take place situation like two processes setting their flag as true. Therefore both of the processes have equal priority to enter into the critical section. Consider that Pi is setting its flag as true in addition to that time a context switch take place so that Pj also sets it flag. Like a result both of them will try to get into the critical section. Therefore neither of them get into the critical section. This circumstance is known as busy waiting. To resolve this Peterson's solution is used.
When programming with threads, there are three very common mistakes that programmers often make: 1. locking twice (depending on the system and type of lock, can cause crashes, h
Explain Deadlock Every process in a set of processes is waiting for an event which only a process in the set can cause.
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Ask question #Minimuexplain the programable clock modes in a computer system m 100 words accepted#
4. Describe priority scheduling algorithm. Consider the following set of processes. Show the order in which the algorithm will schedule these processes. Assume preemptive and non-p
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