Univariate normal distribution, Civil Engineering

Assignment Help:

Univariate normal distribution:

Let X = (XI, X2, ..., Xn,) has the multivariate normal distribution (5.26) of Section 5.4. Show that Y = a X ' follows a univariate normal distribution where a = ( a1 a2 ..., an, ). Also find the mean and the variance of Y.

Solution:

We have

My(t)= E (etY)= E(etaX') = E(eτX')

where τ = ta = (ta1, ta2,..., tan ).

From Example 3 of Section 5.4, we have

MX (t) = E(e tX') = e τμ' +1/2(t∑ t')

Hence

My(t) = MX(τ) = eτμ' - ½ (τ∑τ') =e t(a μ')-1/2 t2(a∑a')

=e tμ -1/2 t2 σ2

Where

1083_Univariate normal distribution.png

842_Univariate normal distribution3.png

Hence

MX(t) = e tμ+1/2 (t2σ2)

in other words Y - N ( μ, σ2 ) where

682_Univariate normal distribution2.png

842_Univariate normal distribution3.png


Related Discussions:- Univariate normal distribution

Define sounding or sensing devices, Define Sounding or Sensing Devices? ...

Define Sounding or Sensing Devices? Sounding devices are effective in checking scour in the streambed adjacent to a bridge. Although sounding/sensing devices can be used indepe

Diferential equations, show that Y = 4e2x - 2e-3x is a solution of initia...

show that Y = 4e2x - 2e-3x is a solution of initial-value problem (d2y)/(dx2)+ (dy)/(dx) - 6y=0 ; y(0)=6 ; y’(0)=2 . is Y = 2e2x - 4e-3x also a solution of this proble

What is dead weight, Dead weight Dead loads are the weight of perma...

Dead weight Dead loads are the weight of permanent components of the structures such as the weight of the elements and spheres, casing weight, weight of the false ceiling a

Explain the allowable strength design (asd), Allowable Strength Design (ASD...

Allowable Strength Design (ASD) Process: - Apply service loads with no load factors - Assume linear elastic analysis of structure - Calculated stresses shall not excee

Choice of pavement - road pavements, Choice of Pavement: The advantag...

Choice of Pavement: The advantages and drawback of the two types of pavements are summarized in Table, to enable a choice to be made. Table : Advantages and drawback of

Illustrate the term - failure due to rupture of steel, Failure Due to Ruptu...

Failure Due to Rupture of Steel This mode of  failure is likely in lightly reinforced concrete members in which the ultimate strength of  steel is attained before the concrete

Simple stresses and strains, Simple stresses and strains: In this simp...

Simple stresses and strains: In this simple stresses and strains you have learnt the concepts of stress, strain, elastic modulus and the primary concepts in application to ana

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd