Car travelling 60 km per hour Overtakes another car travelling at 42km per hour. Asuming each car to be 5metre long . Find totoal time taken during the Overtake. and road distance.

For the car with 60kmph to overtake the first car it should travel a relative distance of 10 m

(5m for catching up and 5m for getting clear ahead)

therefore Srel = 10 m

       Vrel = 60-42 = 18km/hr = 5 m/s

       Relative acceleration = 0 .since both are moving with constant velocities.

Now using relative motion,           S = Vrel × t

therefore time ,t = S / Vrel = 10/5 = 2s

Distance used to overtake is   60 × 5/18 × 2 = 100/3 = 33.33 m