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Homotopy, prove same homotopy type is an equivalent relation

prove same homotopy type is an equivalent relation

integral 0 to pi e^cosx cos (sinx) dx, Let u = sin(x). Then du = cos(x) dx...

Let u = sin(x). Then du = cos(x) dx. So you can now antidifferentiate e^u du. This is e^u + C = e^sin(x) + C.  Then substitute your range 0 to pi. e^sin (pi)-e^sin(0) =0-0 =0

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State clearly that the current in an RLC circuit with an AC source with and without the use of complex variables

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At a point in a loaded member, the stresses relative to an x, y, z coordinate system are given by Calculate the magnitude and direction of the maximum principal stress.

Divison, what is 24 diveded by 3

what is 24 diveded by 3

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