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The sum of two consecutive integers is 41. What are the integers?
Two consecutive integers are numbers in sequence like 4 and 5 or -30 and -29, that are each 1 number apart. Let x = the ?rst consecutive integer. Let x + 1 = the second consecutive integer. Sum is a key word for addition so the equation becomes: (x )+ (x + 1) = 41. Combine like terms on the left side of the equation: 2x + 1 = 41. Subtract 1 from both sides of the equation: 2x + 1 - 1 = 41 - 1. Simplify: 2x = 40. Divide each side of the equation by 2: 2x/2 = 40/2. The variable is now alone: x = 20. Therefore the larger integer is: x + 1 = 21. The two integers are 20 and 21.
Using the expample provided below, if m∠ABE = 4x + 5 and m∠CBD = 7x - 10, Determine the measure of ∠ABE. a. 155° b. 73° c. 107° d. 25° d. ∠CBD and ∠ABE are vert
An unbiased die is tossed twice .Find the probability of getting a 4,5,6 on the first toss and a 1,2,3,4 on the second toss
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2^(x) + 2^(x+3)=36
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Under this section we will be looking at the previous case for the constant coefficient and linear and homogeneous second order differential equations. In this case we need soluti
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