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The sum of two consecutive integers is 41. What are the integers?
Two consecutive integers are numbers in sequence like 4 and 5 or -30 and -29, that are each 1 number apart. Let x = the ?rst consecutive integer. Let x + 1 = the second consecutive integer. Sum is a key word for addition so the equation becomes: (x )+ (x + 1) = 41. Combine like terms on the left side of the equation: 2x + 1 = 41. Subtract 1 from both sides of the equation: 2x + 1 - 1 = 41 - 1. Simplify: 2x = 40. Divide each side of the equation by 2: 2x/2 = 40/2. The variable is now alone: x = 20. Therefore the larger integer is: x + 1 = 21. The two integers are 20 and 21.
The sum of the smallest and largest multiples of 8 up to 60 is?
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tan^2=(secx-1)(secx+1)
Total Contribution per Year for next 10yeras =$1000+$800 =$1800 So Total Future fund Vaule =$1800*(1+1.073+power(1.073,2)+ power(1.073,2)+ power(1.073,3)+ power(1.073,4)+ power
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what is the LCM of 18, 56 and 104 show working
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