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The sum of two consecutive integers is 41. What are the integers?
Two consecutive integers are numbers in sequence like 4 and 5 or -30 and -29, that are each 1 number apart. Let x = the ?rst consecutive integer. Let x + 1 = the second consecutive integer. Sum is a key word for addition so the equation becomes: (x )+ (x + 1) = 41. Combine like terms on the left side of the equation: 2x + 1 = 41. Subtract 1 from both sides of the equation: 2x + 1 - 1 = 41 - 1. Simplify: 2x = 40. Divide each side of the equation by 2: 2x/2 = 40/2. The variable is now alone: x = 20. Therefore the larger integer is: x + 1 = 21. The two integers are 20 and 21.
If tanx+secx=sqr rt 3, 0 Ans) sec 2 x=(√3-tanx) 2 1+tan 2 x=3+tan 2 x-2√3tanx 2√3tanx=2 tanx=1/√3 x=30degree
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If tanA+sinA=m and tanA-sinA=n, show that m 2 -n 2 = 4√mn Ans: TanA + SinA = m TanA - SinA = n. m 2 -n 2 =4√mn . m 2 -n 2 = (TanA + SinA) 2 -(TanA - SinA) 2
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