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Without solving, find out the Wronskian of two solutions to the subsequent differential equation.
t4 y'' - 2t3 y' - t8y = 0
Solution:
First thing that we want to do is divide the differential equation through the coefficient of the second derivative as that requires being a one. This provides us
y'- (2/t) y' t4 y = 0
Here by using (3) the Wronskian is,
W = ce-(∫- (2/t) dt = ce2In t
=
= ct2
(3+2)^2+1-3^2.5
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